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4. Solve the following heat flow problem, being sure to show all your work (you may either type your
work or insert an image): Find the specific heat of 402 grams of graphite that absorbs 1136) of heat
energy as it changes temperature from 26°C to 30°C.
Answer should be 0.7J/gC

Respuesta :

dsdrajlin

Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

  • Mass of graphite (m): 402 g
  • Heat absorbed (Q): 1136 J
  • Initial temperature: 26°C
  • Final temperature: 30 °C
  • Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

c = 0.70 J/g.°C

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