Answer:
D = 0.060732 in
Explanation:
given data
sp. wt. = 500 lb/ft³
diameter = 0.036 in
solution
we get here maximum diameter of rod that is express as
D = [tex]\sqrt{\frac{8 \sigma }{\pi y}}[/tex] ......................1
here [tex]\sigma[/tex] surface tension of water at 60⁰f = 5.03 × [tex]10^{-3}[/tex] lb/ft and y = 500 lb/ft³
so put here value and we will get
D = [tex]\sqrt{\frac{8 \times 5.03 \times 10^{-3} }{\pi \times 500}}[/tex]
D = 0.005061 ft
D = 0.060732 in
