If 4 out of 7 armadillos
carry a defective gene,
about how many
armadillos carry the
normal gene in a
population of 843
armadillos? Round to the nearest whole.

Respuesta :

Answer:

About 231 armadillos

Step-by-step explanation:

Step 1:

4 : 7      Ratio

Step 2:

4x + 7x = 843        Equation

Step 3:

11x = 843      Combine Like Terms

Step 4:

x = 843 ÷ 11      Divide

Step 5:

x ≈ 77

Step 6:

77 × 3      Multiply

Answer:

231

Hope This Helps :)