Answer:
151 ft
48 ft/s
Step-by-step explanation:
h(t)=-16t^2+v₀t+h₀
v₀ = 96 and
h₀ = 7
h(t)=-16t^2+96t+7
The maximum height is at the vertex
The x values of the vertex is at
x = -b/2a = -96/ (2*-16) = -96/-32 =3
Substitute this into the function to find the maximum height
h(3) = -16 ( 3)^2 +96*3+7
-16*9 +288+7
151
The maximum height is 151 ft
Average rate of change from 0 to 3
h(3) - h(0)
---------------
3-0
151 -7
------------
3
144/3
48ft/s
