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Calculate the electrostatic force between a negatively charged PVC pipe (m = 300 g, q = -0.0000007 C) and a positively charged sweater (m = 650 g, q = 0.0000009 C) when they are held 6 cm apart (the centers of their charges are 6 cm apart). Your answer should include the magnitude of the force and clearly state whether they would be pushing or pulling each other with that amount force.

Respuesta :

Answer:

1.575 N

Explanation:

Given that,

Charge on a PVC pipe, q₁ = -0.0000007 C

Charge on a positively charged sweater, q₂ = 0.0000009 C

Separation between charges, d = 6 cm = 0.06 m

We need to find the magnitude of the force between charges. The force between two charges is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 0.0000007 \times 0.0000009 }{(0.06)^2}\\\\F=1.575\ N[/tex]

So, the electrostatic force has a magnitude of 1.575 N.

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