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A car weighs 2,000 kg. It moves along a road by applying a force on the road with a parallel component of 560 N. There are two passengers in the car, each weighing 55 kg. If the magnitude of the force of friction experienced by the car is 45 N, what is the acceleration of the car?

Respuesta :

Answer:

The acceleration of the car is 4.10 m/s².

Explanation:

The acceleration of the car can be found using the following equation:

[tex] F = ma [/tex]    (1)

Where:

F is the force

m is the mass

a is the acceleration

The force is:

[tex]F = F_{p} - F_{f}[/tex]   (2)

Where:

F(p) is the parallel force = 560 N

F(f) is the force of friction = 45 N

By entering equation (2) into (1) we have:

[tex]F_{p} - F_{f} = (m_{c} + m_{p}*2)a[/tex]

[tex] 560 N - 45 N = (2000 kg + 55*2 kg)a [/tex]

[tex] a = \frac{2000 kg + 55*2 kg}{515 N} = 4.10 m/s^{2} [/tex]

Therefore, the acceleration of the car is 4.10 m/s².

I hope it helps you!