Answer:
The volume of container is 39.14 L.
Explanation:
Given data:
Number of moles of neon = 4.0 mol
Pressure of gas = 2.5 atm
Temperature of gas = 25°C
Volume of container = ?
Solution:
we will use general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273 = 298 K
Now we will put the values in formula.
2.5 atm × V = 4.0 mol × 0.0821 atm.L/ mol.K × 298 K
V = 97.86 atm.L /2.5 atm
V = 39.14 L
The volume of container is 39.14 L.
