12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?
(Planck's constant: h=6.63x 10-34 J·s) (E =hu)
a. 1.98x10^-18 Hz
b. 4.58x10^14 Hz
c. 2.16x10^14 Hz
d. 4.39x10^-19 Hz

Respuesta :

Answer:

[tex]u=4.57x10^5GHz[/tex]

Explanation:

Hello.

In this case, given the formula:

[tex]E=h*u[/tex]

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

[tex]u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\ \\u=4.57x10^{14}s^{-1}[/tex]

Or also:

[tex]u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz[/tex]

Best regards.