Respuesta :

Answer:

Step-by-step explanation:

Hello,

[tex]\forall x \in \mathbb{R} \\\\(f+g)(x)=f(x)+g(x)=x^2+1+5-x=x^2-x+4 \\\\(f-g)(x)=f(x)-g(x)=x^2+1-5+x=x^2+x-4[/tex]

Thanks

Answer:

c for the first one and a for the second one

Step-by-step explanation:

just did it on edg