Find a polynomial function with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicity: 3 Zero: 0, multiplicity: 2 Degree: 5

Respuesta :

Given:

Zero: 2, multiplicity: 3

Zero: 0, multiplicity: 2

Degree: 5

Leading coefficient = 1

To find:

The polynomial function.

Solution:

The general form of a polynomial is

[tex]P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}[/tex]

where, a is a constant, [tex]c_1,c_2,...,c_n[/tex] are zeroes with multiplicity [tex]m_1,m_2,...,m_n[/tex].

Using the given information and the general form of a polynomial, we get

[tex]P(x)=a(x-2)^{3}(x-0)^{2}[/tex]

[tex]P(x)=ax^2(x^3-6x^2+12x-8)[/tex]

[tex]P(x)=a(x^5-6x^4+12x^3-8x^2)[/tex]

Leading coefficient is 1, so the value of a is also 1.

[tex]P(x)=1(x^5-6x^4+12x^3-8x^2)[/tex]

[tex]P(x)=x^5-6x^4+12x^3-8x^2[/tex]

Therefore, the required polynomial is [tex]P(x)=x^5-6x^4+12x^3-8x^2[/tex].

The polynomial for the conditions with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicity: 3 Zero: 0, multiplicity: 2 Degree: 5 is given as

[tex]\rm\bold{ y(x) = 1\times (x-2)^3(x-0)^2 }[/tex]

According to the given condition

The given conditions to write the polynomial equations are as follows

Zero 2  and Multiplicity 3

Zero 0 and Multiplicity 2  

Degree of polynomial expression  = 5

Leading coefficient of polynomial expression = 1

Let us consider the polynomial equation has only one variable and hence in general form we can write the equation of polynomial as follows

[tex]\rm y (x) = a(x-\alpha)^m (x-\beta)^n........(1)\\Where \\a = Leading \; coefficient\; of\; polynomial\; expression \\\alpha ,\beta = Roots \; of \; the\; polynomial\; expression\\m\; and \; n \; are \; multiplicities \; of \; the \; roots \; \alpha,\beta \; respectively\\Degree = m+n[/tex]

From the general form of polynomial expression as shown in equation (1) we can write

Polynomial expression for the given  conditions is formulated in equation (2)

[tex]\rm y(x) = 1\times (x-2)^3(x-0)^2 .......(2)[/tex]

So the polynomial for the conditions given in question is expressed as

[tex]\rm\bold{ y(x) = 1\times (x-2)^3(x-0)^2 }[/tex]

For more information please refer to the link given below

https://brainly.com/question/15301188