Answer:
f = 0.9 pounds.
Step-by-step explanation:
Let f = weight of the football.
Let b = weight of the basketball.
Given the following data;
Weight of each basketball, b = 1.37 pounds
Translating the word problem into an algebraic equation, we have;
[tex] 3f + 2b = 5.44[/tex] ..........equation 1
[tex] b = 1.37[/tex] ....................equation 2
Substituting equation 2 into equation 1, we have;
[tex] 3f + 2(1.37) = 5.44[/tex]
[tex] 3f + 2.74 = 5.44[/tex]
Rearranging the equation, we have;
[tex] 3f = 5.44 - 2.74[/tex]
[tex] 3f = 2.7[/tex]
[tex] f = \frac{2.7}{3} [/tex]
f = 0.9 pounds
Therefore, the weight of each football is 0.9 pounds.
