Answer:
Velocity = 94.85m/s
Explanation:
Given the following data ;
Height = 1200m
Vertical distance = 1050m
To find the time, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting into the equation, we have;
[tex] 1200 = 0(t) + \frac {1}{2}*9.8*t^{2}[/tex]
[tex] 1200 = 0 + 4.9*t^{2} [/tex]
[tex] 1200 = 4.9*t^{2} [/tex]
[tex] t^{2} = \frac {1200}{4.9} [/tex]
[tex] t = \sqrt{122.45}[/tex]
t = 11.07 secs
To find the velocity;
Mathematically, velocity is given by the equation;
[tex]Velocity = \frac{distance}{time}[/tex]
Substituting into the above equation;
[tex]Velocity = \frac{1050}{11.07}[/tex]
Velocity = 94.85m/s
Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.
