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If 760 mmHg of pressure was decreased to 458 mmHg, what would be the original volume of a gas that ended up occupying a space of 1072 mL?

Respuesta :

Stephen46

Answer:

646.02 mL

Explanation:

The original volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the original volume

[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]

From the question we have

[tex]V_1 = \frac{458 \times 1072}{760} = \frac{490976}{760} \\ 646.021052...[/tex]

We have the final answer as

646.02 mL

Hope this helps you

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