I. {(0, 0), (0, 1), (0, 2)} II. {(0, 0), (1, 1), (2, 4)} III. {(0, 0), (1, 2), (2, 2)} IV. {(0, 0), (1, 2), (1, 3)} (A) I, II, and III only (B) I and II only (C) II and III only (D) III and IV only

Respuesta :

Answer:

(C) II and III only

Step-by-step explanation:

Given

[tex]I. \{(0, 0), (0, 1), (0, 2)\}[/tex]

[tex]II. \{(0, 0), (1, 1), (2, 4)\}[/tex]

[tex]III. \{(0, 0), (1, 2), (2, 2)\}[/tex]

[tex]IV.\ {(0, 0), (1, 2), (1, 3)\}[/tex]

Required

Which is a function?

A relation is of the form [tex]\{(x_1,y_1),(x_2,y_2),(x_2,y_2),(x_2,y_2).........(x_n,y_n)\}[/tex]

Where [tex]x = domain[/tex] and [tex]y = range[/tex]

And for a relation to be regarded as a function, all its x values must be unique. i.e. unrepeated.

Analyzing the options

[tex]I. \{(0, 0), (0, 1), (0, 2)\}[/tex]

This is not a function because 0 in multiple times for different y values (range)

i.e. (0,0), (0,1) and (0,2)

[tex]II. \{(0, 0), (1, 1), (2, 4)\}[/tex]

This is a function because each of the x values (domains) are unique for different y values (range)

[tex]III. \{(0, 0), (1, 2), (2, 2)\}[/tex]

This is a function because each of the x values (domains) are unique for different y values (range)

[tex]IV.\ {(0, 0), (1, 2), (1, 3)\}[/tex]

This is not a function because 1 in multiple times for different y values (range)

i.e. (1,2) and (1,3)