Answer:
228.7[tex]dm^{3}[/tex]
Explanation:
According to Boyle's law
P1V1 = P2V2
where P1& P2 are initial and final pressure
and V1& V2 and initial and final volumes respectively.
Given:
P1 = 136atm, P2 = 131.6atm
V1 = 142[tex]dm^{3}[/tex]; V2 = ?
V2 = [tex]\frac{P1V1}{P2}[/tex] = [tex]\frac{136*142}{131.6}[/tex]
= 146.7[tex]dm^{3}[/tex]
Total volume, V = V1 + V2
=146.7 + 142
= 228.7[tex]dm^{3}[/tex]
