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A 2.2-kg block starts from rest on a rough inclined plane that makes an angle of 25° with the horizontal. The coefficient of kinetic friction is 0.25. As the block goes 2.0 m down the plane, the mechanical energy of the Earth-block system changes by:

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Answer:

9.77 joules

Explanation:

Given :

Mass, m of block = 2.2kg

Coefficient of kinetic friction, μ = 0.25

Distance, d = 2m

The workdone :

Using the relation :

μ * mgcosθ * d

g = acceleration due to gravity = 9.8m/s²

0.25 * 2.2 * 9.8 * cos25 * 2

= 9.7699979

= 9.77 J

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