traynoran2025
contestada

Find three consecutive even integers such that the sum of the smallest and twice the
second is 20 more than the third. PLEASE SHOW THE WORK ILL GIVE BRAINLIEST

Respuesta :

Jsf09

Answer:

10,11,12

Step-by-step explanation:

X+x+1+x+2

X+2(x+1)=x+2 + 20

X +2x+2 = x+22

3x+2 = x+22

2x +2 = 22

2x = 20

X = 10

Numbers are 10,11,12

Double checking 10+2*11 = 32

12+20 = 32

So it works

Otras preguntas