Answer: The required distance = [tex]\sqrt{10}[/tex] units
Step-by-step explanation:
The shortest distance from a point [tex](x_1,y_2)[/tex] to a line [tex](Ax+By+C=0)[/tex] is the perpendicular distance.
[tex]d=\dfrac{|Ax_1+By_1+C|}{\sqrt{A^2+B^2\\}}[/tex]
Given: Equation of line : = y= -3x + 8 i.e. 3x+y-8=0
Point = (-1,1)
Distance between them = [tex]\dfrac{|3(-1)+1(1)-8}{\sqrt{(3)^2+(1)^2|}}[/tex]
[tex]=\dfrac{|-3+1-8|}{\sqrt{9+1}}\\\\=\dfrac{10}{\sqrt{10}}\\\\=\sqrt{10}[/tex]
Hence, the required distance = [tex]\sqrt{10}[/tex] units
