Answer:
[tex]its \: dimensions \: are \to \\\boxed{w = 17.6cm} \: \boxed{l = 78.4cm} [/tex]
Step-by-step explanation:
[tex]if \to l = 4w + 8 \\ but \\ \: perimeter(p )= l + w = 96 \\ 4w + 8 + w = 96 \\ 5w + 8 = 96 \\ 5w = 96 - 8 \\ 5w = 88 \\ w = \frac{88}{8} \\ \boxed{w = 17.6cm} \boxed{l = 78.4cm}[/tex]