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one number added to twice another number is 23. Four times the first number added to twice the other number is 38. What are the numbers?

Respuesta :

habtamuAbebaw

Answer:

x =5 & y =9

Step-by-step explanation:

let anumber x & y

-(x + 2y = 23)

4x + 2y = 38

-x -2y = -23

4x + 2y = 38

-x + 4x + 2y - 2y = 38-23

3x+0 = 15

3x /3 = 15/3

x = 5 then

5 + 2y = 23

2y = 23-5

2y/2 = 18/2

y = 9

therefore y =18 and x = 5

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