klynn11 klynn11
  • 06-12-2016
  • Chemistry
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Calculate H3O+ when OH- is 2*10 -8

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Аноним Аноним
  • 06-12-2016
relationship between [H3O+] and [OH-] is:

[H3O+] X [OH-] = 1.00 X10^-14

Rearranging gives:
[H3O+] = 1.0X10^-14 / [OH-]

Just plug in and calculate your [H3O+] values
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