Answer:
E = 25 J
Explanation:
Given that,
Spring constant, k = 200
Compression, x = 0.5
We need to find the potential energy stored in the spring. The formula for the stored potential energy in the spring is given by :
[tex]E=\dfrac{1}{2}kx^2[/tex]
Put all the values,
[tex]E=\dfrac{1}{2}\times 200\times 0.5^2\\\\E=25\ J[/tex]
So, 25 J of potential enersy is stored in the spring.
