Answer:
Step-by-step explanation:
Quadratic equation: ax² +bx + c = 0
D = b² - 4ac
1) 4x² - 3x - 2 = 0
a = 4 ; b = -3 ; c = -2
D = (-3)² - 4*4*(-2)
= 9 + 32
= 41
D > 0, So, two distinct real roots.
2) 5x² + 2x - 3 = 0
a = 5 ; b = 2 ; c = -3
D = 2² - 4*5*(-3)
= 4 + 60
= 64
D >0 . So, two distinct real roots.
3)9x² - 6x + 1 = 0
a = 9 ; b = -6 ;c =1
D = (-6)² - 4*9*1
= 36 - 36
= 0
D = 0. So, two equal real roots.
4)3x² + 7x + 8 = 0
a = 3 ; b = 7 ; c = 8
D = 7² - 4*3*8
= 49 - 96
= - 47
D < 0 .So, two roots are complex and different.
5) 8x² + 5x = 0
a = 8 ; b = 5 ; c = 0
D = 5² - 4*8*0
= 25 - 0
= 25
D > 0. So, two distinct real roots.
