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Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 2,890,000 and a mean life span of 10,000 hours. If a monitor is selected at random, find the probability that the life span of the monitor will be more than 8469 hours. Round your answer to four decimal places.

Respuesta :

µ = 17000
σ = sqrt(1690000) = 1300
P(X > 14919)
z= (14919-17000)/1300= -1.60
p(Z < -1.60) = 0.0548
p(X > 14919) = 1 – 0.0548 = 0.9452

Answer:

0.8159

Step-by-step explanation:

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