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The loudest sound, measured in decibels, is calculated using the formula L=10 log, where L is the loudness, and I is the intensity of the sound. What is the intensity of a fire alarm that measures 125 dB loud? Round your answer to the nearest hundredth.

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abidemiokin

The intensity of a fire alarm that measures 125 dB loud is 268,337.29

Formula and expressions

Given the expression L=10 logI

where;

  • L is the loudness
  • I is the intensity of the sound.

Given the following parameters

L = 125dB

Substitute the given parameters into the following

L=10 logI

125 = 10logI

logI = 125/10

logI = 12.5

I = e^12.5

I = 268,337.29

Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29

Learn more on subject of formula here: https://brainly.com/question/657646

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