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Calculate the mass of sample of calcium carbonate containing 5.5 x 10^23 atoms

A. 18.29 g
B. 91.44 g
C. 6.02 x 10^23g
D. not enough information

which one is it?? thank you

Respuesta :

No of moles:-

  • No of molecules/Avagadro no
  • 5.5×10²³÷6.022×10²³
  • 0.91mol

Now

molar mass:-

  • CaCO_3
  • 40+12+48
  • 100g/mol

Mass:-

  • 100(0.91)
  • 91g

Option B

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