The area of the regular pentagon given a side of 10 in is 172.0 in².
A pentagon is an object that is made up of five sides. The sum of the internal angles of a pentagon is 540 degrees.
Area of a pentagon = 1/4√[tex]\sqrt{5 ( 5 + 2 \sqrt{5} ) }[/tex] a²
Where a = side = 10
A = 1/4√[tex]\sqrt{5 ( 5 + 2 \sqrt{5} ) }[/tex] 10²
A = 172.02 in²
To learn more about pentagons, please check: https://brainly.com/question/17054992
#SPJ1
