Ethangk98 Ethangk98

06-02-2017
Mathematics

contestada

Factor 16x^2 + 16x + 4 completely
a. (16x + 4)(x + 1)
b. (4x + 2)(4x - 2)
c. 4(2x + 1)^2

Respuesta :

texaschic101 texaschic101

06-02-2017

16x^2 + 16x + 4...common factor is 4
4(4x^2 + 4x + 1) =
4(2x + 1)(2x + 1) =
4(2x + 1)^2 <===

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