The solubility of barium carbonate, BaCo₃ is 4.5 x 10⁻⁵ M.
To find the solubility, the given values are,
Ksp = 2.0·10⁻⁹.
Here, s(BaCO₃) = ?M.
In chemistry, Solubility is the ability of a substance, the solute, to form a solution with another substance, the solvent.
Formula for solubility is,
Ksp = [A^+]^a [B^-]^b
Ksp = solubility product constant
A^+ = cation in an aqueous solution
B^- = anion in an aqueous solution
a, b = relative concentrations of a and b
The Chemical reaction of Barium carbonate is :
BaCO₃(s) → Ba²⁺(aq) + CO₃²⁻(aq).
s(BaCO₃) = s(Ba²⁺) =s(CO₃²⁻) = x.
Ksp = s(Ba²⁺) · s(CO₃²⁻).
Ksp = x · x.
2.0·10⁻⁹ = x².
x = √2.0·10⁻⁹
= 4.47x10⁻⁵ M.
So, The solubility of Barium carbonate is 4.5x10⁻⁵ M.
Hence, Option D is the correct answer.
Learn more about Solubility,
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