Calculate the solubility of barium carbonate, baco3, in pure water. ksp = 2.0 x 10-9
a) 3 x 10-3 m
b) 3.2 x 10-5 m
c) 2.0 x 10-5 m
d) 4.5 x 10-5 m

Respuesta :

The solubility of barium carbonate, BaCo₃ is 4.5 x 10⁻⁵ M.

To find the solubility, the given values are,

Ksp = 2.0·10⁻⁹.

Here, s(BaCO₃) = ?M.

What is Solubility?

In chemistry, Solubility is the ability of a substance, the solute, to form a solution with another substance, the solvent.

Formula for solubility is,

                           Ksp = [A^+]^a [B^-]^b

Ksp = solubility product constant

A^+ = cation in an aqueous solution

B^- = anion in an aqueous solution

a, b = relative concentrations of a and b

The Chemical reaction of Barium carbonate is :

BaCO₃(s) → Ba²⁺(aq) + CO₃²⁻(aq).

s(BaCO₃) = s(Ba²⁺) =s(CO₃²⁻) = x.

Ksp = s(Ba²⁺) · s(CO₃²⁻).

Ksp = x · x.

2.0·10⁻⁹ = x².

x = √2.0·10⁻⁹

  = 4.47x10⁻⁵ M.

So, The solubility of Barium carbonate is 4.5x10⁻⁵ M.

Hence, Option D is the correct answer.

Learn more about Solubility,

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