Respuesta :
Moles of MgS2O3 = 223/molar mass of MgS2O3
= 223/136.42
= 1.634 moles.
Hope this helps!
= 223/136.42
= 1.634 moles.
Hope this helps!
Answer: 1.63 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=[/tex]
Given mass = 223 g
Molar mass = 136.4
[tex]\text{Number of moles}=\frac{223g}{136.4g/mol}=1.63moles[/tex]
Thus there are 1.63 moles in 223 g of the compound.