Respuesta :
The molecular formula is C10H10O2.
What is molecular formula?
The number of atoms of each constituent element that constitute a given molecule are described by its molecular formula.
Mass of the compound extracted from the bark of the sassafras tree =40.5mg
Mass of CO2 obtained= 110.0mg
Mass of water obtained=22.5g
Calculation of percentage of Carbon, Hydrogen and Oxygen
12 g of Carbon is present in 44 g of CO2. Similarly 2 g of H is present in 18 g of water. Using this we calculate
Percentage of C = 12/44.mass of CO2/ total mass of compound *100
= 12/44.110.0/ 40.5 *100
=74.07
Percentage of H = 2/18.mass of H2O/ mass of compound *100
= 2/18.22.5/ 40.5 *100
=6.17
Percentage of O =100-6.17-74.07
=19.76 ( As compound contains only C H and O).
Hence, Empirical Formula is C5H5O.
Molecular mass of compound= 162g/mol
Empirical mass = 60+5+16=81g/mol
So, multiplying factor (n) = Molar mass/empirical mass= 162/81=2
So, Molecular formula= (C5H5O)2= C10H10O2.
Therefore, the molecular formula is C10H10O2.
To learn more about molecular formula from the given link.
https://brainly.com/question/15960587
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