KendallHouston KendallHouston

07-03-2017
Mathematics

contestada

Given sinx=0.9 , what is cosx ?

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jdoe0001 jdoe0001

07-03-2017

[tex]\bf \textit{Pythagorean Identities} \\ \quad \\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\\\ cos(\theta)=\pm\sqrt{1-sin^2(\theta)}\\\\ -----------------------------\\\\ thus \\\\\\ cos(x)=\pm \sqrt{1-(0.9)^2}[/tex]

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26-04-2021

The answer is cos x = 0.44

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