Respuesta :

irspow
Since BC and CD are tangent to the circle.  The half angle of BCD=90-53=37

So the angle BCD=74°

Based on the tangent theorem, angle BCD is: c. 74°

Tangent Theorem

  • Based on the tangent theorem, angle BCD = 2(angle BCA).
  • Also, angle CBA is a right angle = 90 degrees.

Thus:

angle BCA = 180 - 90 - 53

angle BCA = 37°

angle BCD = 2(angle BCA)

  • Substitute

angle BCD = 2(37).

angle BCD = 74°

Therefore, based on the tangent theorem, angle BCD is: c. 74°

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