Five pennies, 3 dimes, and 4 quarters are placed in a bag. What is the probability of selecting a penny and then a dime, given the first coin is not returned to the bag after it is drawn?
There are 12 coins in the bag. For the first case, the probability that a penny is selected from the bag is 5/12 because there are 5 pennies in the bag. Also, the next one is 3/11. Multiplying the probabilities, (5/12)(3/11) = 8/121
