Respuesta :
First, plug x=10 and x=20 into the formula:
10^2+90+18
190+18
208
20^2+180+18
400+198
598
598-208=390
390/10 = 39
The average rate of change is 39
10^2+90+18
190+18
208
20^2+180+18
400+198
598
598-208=390
390/10 = 39
The average rate of change is 39
Answer:
The average rate of change for f(x) from x = 10 to x = 20 is 39.
Step-by-step explanation:
The given function is
[tex]f(x)=x^2+9x+18[/tex]
[tex]f(10)=(10)^2+9(10)+18=208[/tex]
[tex]f(20)=(20)^2+9(20)+18=598[/tex]
The formula for average rate of change for a function is
[tex]m=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]
We have to find the average rate of change for f(x) from x = 10 to x = 20.
[tex]m=\frac{f(20)-f(10)}{20-10}[/tex]
[tex]m=\frac{598-208}{10}[/tex]
[tex]m=\frac{390}{10}[/tex]
[tex]m=39[/tex]
Therefore the average rate of change for f(x) from x = 10 to x = 20 is 39.