330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°
c. the specific heat of aluminum is what is the final temperature of the system, assuming no heat is exchanged with the surroundings?
the final temperature of the system is 32.5° we know, H = mcT where, H = Heat content of the body m = Mass, c = Specific heat T = Change in temperature According to to the Principle of Calorimetry
The net heat remains constant i.e. ⇒ the heat given by water = heat accepted by the aluminum container. ⇒ 330 x 1 x (45 - T) = 855 x [tex] \frac{900}{4200} [/tex] x (T - 10)
