2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
m(Pb(NO₃)₂)=9.9 g
m'(PbO)=5.5 g
the theoretical mass of lead oxide is:
m(PbO)=M(PbO)*m(Pb(NO₃)₂)/M(Pb(NO₃)₂)
the percent yiled of lead oxides is:
w=m'(PbO)/m(PbO)=m'(PbO)M(Pb(NO₃)₂)/M(PbO)*m(Pb(NO₃)₂)
w=5.5*331.2/(223.2*9.9)=0.824 (82.4%)