A chemist prepares a solution by dissolving 0.3 mole of CaCl2 in enough water to make 1000 mL of solution. What is the molar concentration of chloride ions?

Respuesta :

[tex] CaCl_{2} [/tex] dissolves in water to give [tex] Ca^{2+} [/tex] and [tex] Cl^{-} [/tex] ions according to the following reaction:

[tex] CaCl_{2} [/tex]  -------->  [tex] Ca^{2+} [/tex]  + 2[tex] Cl^{-} [/tex]

So, according to the above reaction, 1 mole of [tex] CaCl_{2} [/tex] produce 2 moles of [tex] Cl^{-} [/tex] ion,

So, 0.3 mole will give = 0.3 x 2 = 0.6 moles of  [tex] Cl^{-} [/tex] ion

So, Molar concentration = [tex]\frac{0.6moles}{1L} = 0.6[/tex]

Note: 1L = 1000mL