06-09-2017
Mathematics

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I do not know how to do this

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WojtekR WojtekR

06-09-2017

[tex]g=\dfrac{x-c}{x}\quad|\cdot x\\\\\\gx=x-c\\\\gx-x=-c\\\\x(g-1)=-c\quad|:(g-1)\\\\\boxed{x=-\frac{c}{g-1}=\frac{c}{1-g}}[/tex]

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