contestada

The distance D that a spring is stretched by a hanging object varies directly as the weight W of the object. If a 27-kg object stretches a spring 53 cm, find the distance when the weight is 13-kg. Round your answer to the nearest whole centimeter.

Respuesta :

josh09132
Cross multiply: 27x = 53*13 
x = 53*13/27 = 25.52 
Rounds to 26. 

Answer:

The distance when the weight is 13-kg is [tex]25.51\\[/tex] cm

Step-by-step explanation:

[tex]27\\[/tex] Kg mass of object stretches the spring by [tex]53 \\[/tex] cm

[tex]1 \\[/tex] kg mass of object stretches the spring by [tex]\frac{53}{27} \\[/tex] cm

[tex]13 \\[/tex] kg mass of object stretches the spring by [tex]\frac{53}{27} * (13)\\= 25.51 \\[/tex] cm