Respuesta :
LCM of x+5 and x is x(x+5)
multiplying each term by x(x+5) gives us the numerator:-
= 3x^2 - (x-5)(x+5)
= 3x^2 - (x^2 - 25)
= 2x^2 + 25
so answer is
2x^2 + 25 / x(x+5)
Its B
multiplying each term by x(x+5) gives us the numerator:-
= 3x^2 - (x-5)(x+5)
= 3x^2 - (x^2 - 25)
= 2x^2 + 25
so answer is
2x^2 + 25 / x(x+5)
Its B