Baileyyy123
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Rectangle J’K’L’M shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV.

What will be the location of T’ in the image trapezoid S’T’U’V’?

A. (15, 2)

B. (18, 2)

C. (18, -2)

D. (15, -2)

Rectangle JKLM shown on the grid is the image of rectangle JKLM after transformation The same transformation will be applied on trapezoid STUV What will be the class=

Respuesta :

The answer is (18, 2) this is because the original figure JKLM used the rule (x+13, y-3) sorry not sure if I put that rule in the correct order.

The correct answer is:

B. (18, 2)

Explanation:

The points of the pre-image JKLM are:

J(-7, -6); K(-4, -6); L(-4, -2); and M(-7, -2).

The points of image J'K'L'M' are:

J'(6, -9); K'(9, -9); L'(9, -5); and M'(6, -5).

Each point has moved horizontally 13 units and vertically -3 units; this gives us the translation <13, -3>.

Applying this to T, we have:

T'(5+13, 5-3) = (18, 2)

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