Respuesta :

[tex]\bf (f\circ g)(x)\implies f(~~g(x)~~)\implies h(x)\implies (9x+6)^8\\\\ -------------------------------\\\\ \textit{a combination off several could just be}\quad \begin{cases} f(x)=x^8\\ g(x)=9x+6 \end{cases} \\\\\\ f(~~g(x)~~)=[g(x)]^8\implies f(~~g(x)~~)=(9x+6)^8\impliedby h(x)[/tex]

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