Knowing that the tow rectangular viewing area peremiters are similar, we can establish a rule of three to find the viewing area of the 46-inch widescreen.
[tex] \frac{42}{144.4} = \frac{46}{x} [/tex]
Now we solve for x to find the viewing area of the 46-inch widescreen:
[tex]x= \frac{(46)(144.4)}{42} [/tex]
[tex]x=158.6[/tex]
We can conclude that the viewing area perimeter of the 46-inch widescreen television set is approximately 158.6 inches.
