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In an equilateral hexagon, four of the exterior angles each have a measure of x°. the other two exterior angles each have a measure of twice the sum of x and 48. give the measures of the exterior angles in order from least to greatest.

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W0lf93

A hexagon has 6 sides. Four of the exterior angle have an angle x. The other
two angles have angle 2(x + 48). Since rhe sum of the exterior angles of a
regular polygon equal 360 degrees.
 We have x + x + x + x + 2(x +48) + 2(x + 48) = 360
 4x + 2x + 2x + 96 + 96 = 360
 8x + 192 = 360
 8x = 360 - 192 
 8x = 168
 x = 21
 For the other two sides the angles are 2(21 + 48) = 138
 So we have 21, 21, 21, 21, 138, 138

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