Please check this for me?
Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas.

My answer: PbS (s) + O2 (g) --> PbO (s) + SO2 (g)

I wanted to know if I'm correct before I balance.

Question

07-03-2018
Chemistry

contestada

Please check this for me?
Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas.

My answer: PbS (s) + O2 (g) --> PbO (s) + SO2 (g)

I wanted to know if I'm correct before I balance.

Respuesta :

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aencabo aencabo · Answer 1 · 2018-03-17T15:10:09+01:00

The answer is
2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g)

Your answer is not yet balanced because you have 3 oxygen atoms. it should be balanced by multiplying both side by 2 such as the balanced equation I made. To check it, I will explain why your answer is not yet balanced.

check: (from your equation)
1-Pb-1
1-S-1
2 -O-3
the difference between the reactant and the product of Oxygen will prove that it is not yet balanced.

If you use 2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g), to check it:
2-Pb-2
2-S-2
6 -O-6
then this is now balance

Please check this for me? Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas. My answer: PbS (s) + O2 (g) --> PbO (s) + SO2 (g) I wanted to know if I'm correct before I balance.

Respuesta :

Otras preguntas

Please check this for me?
Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas.

My answer: PbS (s) + O2 (g) --> PbO (s) + SO2 (g)

I wanted to know if I'm correct before I balance.